SOLUTION: square poster has sides measuring 2ft less than the sides of a square sign. If the difference between their areas is 52 sq ft find the length of the sides of the poster & sign.

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: square poster has sides measuring 2ft less than the sides of a square sign. If the difference between their areas is 52 sq ft find the length of the sides of the poster & sign.       Log On


   

Question 705076: square poster has sides measuring 2ft less than the sides of a square sign. If the difference between their areas is 52 sq ft find the length of the sides of the poster & sign.
Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
sign side length: x
poster side length: x-2

x^2 - (x-2)^2 = 52
x^2 - (x^2 - 4x + 4) = 52
4x - 4 = 52
4x = 56
x = 14

sign side length = 14 ft
poster side length = 12 ft