SOLUTION: Help is needed. Thanks! Graph the following and justify your answer. y=2^x y=log2 (x)

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: Help is needed. Thanks! Graph the following and justify your answer. y=2^x y=log2 (x)      Log On


   



Question 70480This question is from textbook Elementary and Intermediate Algebra
: Help is needed. Thanks!
Graph the following and justify your answer.
y=2^x
y=log2 (x)
This question is from textbook Elementary and Intermediate Algebra

Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
Help is needed. Thanks!
Graph the following and justify your answer.
y=2^x
y=log2 (x)
:
For y=2^x
Let x=-1
y=2^-1
y=1/2 Plot (-1,1/2)
Let x=0
y=2^0
y=1 Plot (0,1)
Let x=1
y=2^1
y=2 Plot (1,2)
Let x=2
y=2^2
y=4 Plot (2,4)
Connect your points and you have:
graph%28300%2C200%2C-10%2C10%2C-10%2C10%2C2%5Ex%29
For y=log2(x)
Let y=-1
-1=log2(x)
2^-1=x
1/2=x Plot (1/2,-1)
Let y=0
0=log2(x)
2^0=x
1=x Plot (1,0)
Let y=1
1=log2(x)
2^1=x
2=x Plot (2,1)
Let y=2
2=log2(x)
2^2=x
4=x Plot (4,2)
Connect the points and you have:
graph%28300%2C200%2C-10%2C10%2C-10%2C10%2Cln%28x%29%2Fln%282%29%29
Happy Calculating!!!