SOLUTION: Help is needed. For the exponential function ex and logarithmic function log x, graphically show the effect if x is doubled. Thank you!

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: Help is needed. For the exponential function ex and logarithmic function log x, graphically show the effect if x is doubled. Thank you!      Log On


   



Question 70478This question is from textbook Elementary and Intermediate Algebra
: Help is needed.
For the exponential function ex and logarithmic function log x, graphically show the effect if x is doubled. Thank you!
This question is from textbook Elementary and Intermediate Algebra

Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
Help is needed.
For the exponential function ex and logarithmic function log x, graphically show the effect if x is doubled.
f(x)=e^x looks like this:
graph%28300%2C200%2C-10%2C10%2C-10%2C10%2C2.718281828%5Ex%29
If you doubled x it would make your graph grow exponentially by 2. e is about 2.71828, so at x=1, the graph would normally be about 2.71828 and when x=2 y would be about 7.389. If x is doubled, at x=1 y would be about 7.389 and x = 2 would cause the graph to be about 54.5982.
Here are the two graphs graphed together:
graph%28300%2C200%2C-10%2C10%2C-10%2C10%2C2.718281828%5Ex%2C2.7182812828%5E%282x%29%29
f(x)=ln(x) looks like this:
graph%28300%2C200%2C-10%2C10%2C-10%2C10%2Cln%28x%29%29
For this graph is x was doubled, there is less of a dramatic change in y. In the original graph when x=2.718 y is about 1. When x is bout 7.389, y is about 2. If you only double x, the change of y would be less than 1.
Here are the two graphs graphed together.
graph%28300%2C200%2C-10%2C10%2C-10%2C10%2Cln%28x%29%2Cln%282%2Ax%29%29
f(x)=e^x and f(x)=ln(x) are inverse functions, so they are reflections about the line y=x. I will graph the two functions and y=x so you can see what I mean:
graph%28300%2C200%2C-10%2C10%2C-10%2C10%2C2.718281828%5Ex%2Cln%28x%29%2Cx%29
I'm sorry I didn't read the directions thoroughly before. I hope this is clearer.
Happy Calculating!!!!