SOLUTION: Ok this is a parabola question.
What are the zeros for the equation y=-2x^2+5x+3
The vertex form is y=-2(x-5/4)^2 +49/8.
This seems like a very difficult problem, and I s
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-> SOLUTION: Ok this is a parabola question.
What are the zeros for the equation y=-2x^2+5x+3
The vertex form is y=-2(x-5/4)^2 +49/8.
This seems like a very difficult problem, and I s
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Question 704685: Ok this is a parabola question.
What are the zeros for the equation y=-2x^2+5x+3
The vertex form is y=-2(x-5/4)^2 +49/8.
This seems like a very difficult problem, and I sure can't figure it out. Any help would be greatly appreciated! Thanks sooo much!!! Answer by nerdybill(7384) (Show Source):
You can put this solution on YOUR website! What are the zeros for the equation y=-2x^2+5x+3
.
The "zeros" are the "roots" of the quadratic -- or, where it crosses the x-axis.
So, you basically set y equal to zero and solve for x:
given:
y=-2x^2+5x+3
setting y to zero:
0=-2x^2+5x+3
multiplying both sides by -1:
0=2x^2-5x-3
factoring the right side:
0=(2x+1)(x-3)
x = {-1/2, 3} (zeros)
