SOLUTION: I have to sketch and identify x^2=y^2=48 and I have no clue, could you help me please????

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: I have to sketch and identify x^2=y^2=48 and I have no clue, could you help me please????      Log On


   

Question 704526: I have to sketch and identify x^2=y^2=48 and I have no clue, could you help me please????
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
x^2+y^2=48 is a circle with center (0,0) and radius sqrt(48) since it is in the form (x-h)^2 + (y-h)^2 = r^2 where (h,k) is the center, r is the radius.


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