SOLUTION: What are the foci of the hyperbola given by the equation (x+10)^2/25 - (y+1)^2/9 = 1?

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Question 704412: What are the foci of the hyperbola given by the equation (x+10)^2/25 - (y+1)^2/9 = 1?
Answer by Edwin McCravy(20064) About Me  (Show Source):
You can put this solution on YOUR website!


(x+10)^2/25 - (y+1)^2/9  = 1? 

(x+10)ｲ   (y+1)ｲ 
覧覧覧 - 覧覧覧 = 1
  5ｲ       3ｲ

This is a hyperbola that looks like this:   }{

and has equation

(x-h)ｲ   (y-k)ｲ 
覧覧覧 - 覧覧覧 = 1
  aｲ       bｲ 

where center = (h,k) = (-10,-1)
a = semi-transverse axis = 5, 
b = semi conjugate axis = 3 
foci (hｱc,k) where cｲ = aｲ+bｲ 
                   cｲ = 5ｲ+3ｲ
                   cｲ = 25+9
                   cｲ = 34
                    c = √34
  
foci (hｱc,k) = (-10ｱ√34, -1)

Edwin