SOLUTION: OK, so my home work is on Algebra 1 My problem is about "GEOMETRY: PARALLEL and PERPENDICULAR LINES. Write the slope-intercept form of an equation for the line that passes throu

Algebra ->  Parallelograms -> SOLUTION: OK, so my home work is on Algebra 1 My problem is about "GEOMETRY: PARALLEL and PERPENDICULAR LINES. Write the slope-intercept form of an equation for the line that passes throu      Log On


   

Question 704258: OK, so my home work is on Algebra 1
My problem is about "GEOMETRY: PARALLEL
and PERPENDICULAR LINES.
Write the slope-intercept form of an equation for the line that passes through the given point and is PARALLEL to the graph of each equation.
(2,3) Y=X+5
PLease help
Found 2 solutions by lynnlo, KMST:
Answer by lynnlo(4176) About Me  (Show Source):
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
Parallel lines have the same slope,
because slope is the change in y for an x increase of 1,
and that is the tangent of the angle the line makes with the positive x axis.


y=x%2B5 is the equation of a line in highlight%28slope-intercept%29 form.
That is the unique and very useful form that starts with "y=".
The number added at the end (5 in this case) is the intercept,
the y value for x=0, and therefore the y- coordinate of the point where the line "intercepts" the y-axis.
The number multiplying the x (an invisible 1 in this case) is the slope.
You can see that for x=0, y=5, but if you increase x by one,
for x=1, y=1+5 has increased by 1.

The line parallel to y=x%2B5 will have highlight%28slope=1%29 and an intercept, b to be determined.
Its equation will be y=x%2Bb
We know that for that line the
point with x=2 has y=3 so substituting into y=x%2Bb we get
3=2%2Bb --> 3-2=b --> highlight%28b=1%29
and the equation is highlight%28y=x%2B1%29