SOLUTION: A bag contains seven red apples and nine green apples. What is the probability of choosing a green apple and then a red apple without replacing? A. 9/7 B. 63/256 C. 21/80 D. 2/3

Algebra ->  Probability-and-statistics -> SOLUTION: A bag contains seven red apples and nine green apples. What is the probability of choosing a green apple and then a red apple without replacing? A. 9/7 B. 63/256 C. 21/80 D. 2/3      Log On


   



Question 704151: A bag contains seven red apples and nine green apples. What is the probability of choosing a green apple and then a red apple without replacing?
A. 9/7 B. 63/256 C. 21/80 D. 2/3

Answer by filboi(35) About Me  (Show Source):
You can put this solution on YOUR website!
The probability of getting a red apple is 9/16.
The probability of getting a green apple is 7/15. There are only 15 apples in total after picking 1 at the beginning.
So the equation becomes:
P=%289%2F16%29%287%2F15%29=21%2F80
So the answer is C.