SOLUTION: given that {{{-1}}} and {{{h}}} are roots of quadratic equation {{{(3x-1)(x-2)=p(x-1)}}} , where {{{p}}} is constant, find the value of {{{h}}} and {{{p}}}. I need steps . {{{THA

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: given that {{{-1}}} and {{{h}}} are roots of quadratic equation {{{(3x-1)(x-2)=p(x-1)}}} , where {{{p}}} is constant, find the value of {{{h}}} and {{{p}}}. I need steps . {{{THA      Log On


   

Question 703987: given that -1 and h are roots of quadratic equation %283x-1%29%28x-2%29=p%28x-1%29 , where p is constant, find the value of h and p.
I need steps . THANKS
Answer by josgarithmetic(39613) About Me  (Show Source):
You can put this solution on YOUR website!
You might use two forms of the quadratic equation. You have the form in which you are given, and you also have,... 3x%5E2-%287%2Bp%29x%2Bp%2B2=0.

Use your given root, x=-1 in your given equation and find that p=-6.

Now that you have a value for p, use it for a revised form of the general form of your equation: 3x%5E3-x-4=0.
Can this be factored, or do we need general solution for quadratic equation?
FACTORABLE: %283x-4%29%2A%28x%2B1%29=0;
The other root, h, when 3x-4=0, x=4%2F3, the "other root".