SOLUTION: Trying to change the following equation into slope intercept form. 3/4x-3y=-5 I first moved the 3/4 x to the other side to get -3y=-3/4x-5 I am just wondering how you then

Algebra ->  Linear-equations -> SOLUTION: Trying to change the following equation into slope intercept form. 3/4x-3y=-5 I first moved the 3/4 x to the other side to get -3y=-3/4x-5 I am just wondering how you then      Log On


   

Question 703807: Trying to change the following equation into slope intercept form.
3/4x-3y=-5
I first moved the 3/4 x to the other side to get
-3y=-3/4x-5
I am just wondering how you then get the y by itself? I would divide by -3 but how do I divide -3/4 by -3?
Or, do I need to get rid of the fraction to start off? If so, how do I do that?
Thanks
Found 2 solutions by Alan3354, stanbon:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Trying to change the following equation into slope intercept form.
3/4x-3y=-5
I first moved the 3/4 x to the other side to get
-3y=-3/4x-5
I am just wondering how you then get the y by itself? I would divide by -3 but how do I divide -3/4 by -3?
--------------
(-3/4)/(-3) = 1/4
----
--> y = (1/4)x + 5/3

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Trying to change the following equation into slope intercept form.
3/4x-3y=-5
-----
Since you want y to be positive, add 3y to both sides to get:
3y = (3/4)x + 5
----
Divide thru by 3 to get:
y = (1/4)x + (5/3)
======
That is the slope-intercept form.
Cheers,
Stan H.
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