SOLUTION: Can anyone please help me with the last part of this expression (t^2-t-6)(t-3)^-1. My answer is t^2-t-6/t-3 and i would like to know how they factor to (t+2)

Algebra ->  Test -> SOLUTION: Can anyone please help me with the last part of this expression (t^2-t-6)(t-3)^-1. My answer is t^2-t-6/t-3 and i would like to know how they factor to (t+2)      Log On


   

Question 703751: Can anyone please help me with the last part of this expression (t^2-t-6)(t-3)^-1.
My answer is t^2-t-6/t-3 and i would like to know how they factor to (t+2)
Answer by Simnepi(216) About Me  (Show Source):
You can put this solution on YOUR website!
you are correct but you haven't finished!
factorise the numerator t%5E2-t-6 this gives
(t+2)(t-3)
(I've missed out a few steps, but if you need clarification ask me!)
Putting the fraction back together gives
%28%28t%2B2%29%28t-3%29%29%2F%28t-3%29
looking at numerator and denominator they both contain the factor (t-3) which will cancel with each other. giving
%28%28t%2B2%291%29%2F1 which is just (t+2)