Question 703668: I need step by step instructions on how to find the x and y intercepts for the following:
y=x^3+x^2-4x-4
Answer by lynnlo(4176)   (Show Source):
You can put this solution on YOUR website! YOUR ANSWER TO YOUR PROBLEM IS:X INTERCEPT IS (2,0),(-2,0),(-1,0)
Y INTERCEPT IS (0,-4)
X INTERCEPT OF A LINE IS THE POINT WHERE THE LINE CROSSES THE X AXIS
Y INTERCEPT===================================================Y AXIS
WHERE X AND Y VALUES =0
I HAVE SET-UP AN EXAMPLE:
3X+4Y=12
(1)FIND X INTERCEPT,LET Y=0,SOLVE FOR X
3X+4(0)=12
3X+0=12
3X=12
X=12/3
X=4
(2) FIND THE Y INTERCEPT, LET X=0 AND SOLVE FOR Y
3(0)+4Y=12
0+4Y=12
4Y=12
Y=12/4
Y=3
SO,THE X INTERCEPT IS (4,0)
Y INTERCEPT IS (0,3)
I HOPE THIS EXAMPLE WILL HELP YOU TO UNDERSTAND ,,,X AND Y INTERCEPTS
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