SOLUTION: Find the slope of a line perpendicular to the line that has x−intercept −3 and has y−intercept of 4
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-> SOLUTION: Find the slope of a line perpendicular to the line that has x−intercept −3 and has y−intercept of 4
Log On
multiply equation by LCD -12
so 4x-3y=-12
3y=4x-12
y = 4/3 x -4
slope = m= 4/3
Perpendicular line will have slope which is negative reciprocal of 4/3
= -3/4
The line is passing through (-3,0)
equation of line will be
(y-y1) = m(x-x1)
y-(-3)=-3/4(x-0)
y+3= -3/4 x
y= -3/4 x -3