SOLUTION: the cooling system of car has a capacity of 15 liters. If the system is currently filled with a mixture that is 40% anitfreeze, how much if this mixture should be drained and repla
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Question 703384: the cooling system of car has a capacity of 15 liters. If the system is currently filled with a mixture that is 40% anitfreeze, how much if this mixture should be drained and replaced with pure anitfreeze so that the system is filled with a solution this is 50% antifreeze? Found 2 solutions by nshah11, josmiceli:Answer by nshah11(47) (Show Source):
You can put this solution on YOUR website! Assume x liters of the mixture should be drained. The x liters consists of 0.40(x) antifreeze.
Remaining antifreeze after x liters are drained = 15(0.4) - 0.4(x)
Assume x liters of pure antifreeze is added. If so, then total antifreeze = 6 - 0.4(x) + x = 6 + 0.6(x)
(6 + 0.6(x))/(15) = 1/2
12 + 1.2x = 15
x = 2.5 liters
You can put this solution on YOUR website! Let = liters of mixture to be drained
and replaced with pure antifreeze
At the start, liters of pure antifreeze in 40% mixture = liters of pure antifreeze in mixture drained
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2.5 liters of mixture must be drained
and replaced with pure antifreeze
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check:
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