SOLUTION: How to find the root? Can you send me the answer and show me the steps to solve the problem. Thank you, Freda 1. solve 4x^4 = 12x^2. 2. solve x^4 - 30x^2+ 125. 3. so

Algebra ->  Exponents -> SOLUTION: How to find the root? Can you send me the answer and show me the steps to solve the problem. Thank you, Freda 1. solve 4x^4 = 12x^2. 2. solve x^4 - 30x^2+ 125. 3. so      Log On


   



Question 703243: How to find the root? Can you send me the answer and show me the steps to solve the problem. Thank you, Freda
1. solve 4x^4 = 12x^2.
2. solve x^4 - 30x^2+ 125.
3. solve x^2 -1 = 0.
4. solve -2x + 1>7.
5. evaluate(1/2)^3.

Answer by Simnepi(216) About Me  (Show Source):
You can put this solution on YOUR website!
1.
divide both sides by the greatest factor they share, which is 4x%5E2
giving
%284x%5E4%29%2F%284x%5E2%29=%2812x%5E2%29%2F%284x%5E2%29
simplifying gives
x%5E2=3
take square roots to give
x=sqrt%283%29
2.
I'm not sure how to do this one i suggest you re-post the question.
3.
This is the same as x%5E2-1%5E2
this is known as 'the difference of two perfect squares' and is factorised like this
(x+1)(x-1).
(If you had a different square number , x%5E2-9 it would factorise like
(x+3)(x-3).)
so
(x+1)(x-1)=0
therefore
(x+1)=0 or (x-1)=0
so x= -1 or x= 1
4.
treat inequalities like equations!
-2x+1>7
-2x>6 (subtracting 1 from both sides)
x>-3 (dividing both sides by -2)
5.
%281%2F2%29%5E3= %281%5E3%29%2F%282%5E3%29
giving
1%2F8