SOLUTION: Can someone show me how this equation (a^2)^3/b^3÷(a/b^2)^-2 simplifies to a^8/b^7
i tried and i worked it out to be something like a^5/b
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-> SOLUTION: Can someone show me how this equation (a^2)^3/b^3÷(a/b^2)^-2 simplifies to a^8/b^7
i tried and i worked it out to be something like a^5/b
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Question 703217: Can someone show me how this equation (a^2)^3/b^3÷(a/b^2)^-2 simplifies to a^8/b^7
i tried and i worked it out to be something like a^5/b Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! (a^2)^3/b^3÷(a/b^2)^-2 simplifies to a^8/b^7
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(a^6)/(b^3) / (b^2/a)^2
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= (a^6/b^3) / (b^4/a^2)
Invert the denominator and multiply to get:
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= (a^6/b^3) * (a^2/b^4)
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= a^8/b^7
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Cheers,
Stan H.
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