SOLUTION: Julio wants to make 10 fluid ounces of a 56% saline solution by mixing together a 40% saline solution and a 60% saline solution. How much of each solution must he use?

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Question 703184: Julio wants to make 10 fluid ounces of a 56% saline solution by mixing together a 40% saline solution and a 60% saline solution. How much of each solution must he use?
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
The description and question make no physical sense, but here is the arithmetic:

d for 40% solution, u for 60% solution.
%28.4%2Ad%2B.6%2Au%29%2F%2810%29=.56
40%2Ad%2B60%2Au=560
4%2Ad%2B6%2Au=56
2%2Ad%2B3%2Au=28

Want to have 10 fluid ounce, so d%2Bu=10. If multiply both sides of this one by 2, we get equivalent equation, 2d%2B2u=20.

If we now subtract 2d%2B2u=20 from 2%2Ad%2B3%2Au=28, we get u = 8 fluid ounces. value for d can be easily computed.