You can put this solution on YOUR website! 1/x² - 1/y² over 1/xy² - 1/x²y²
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(x^2-y^2)/(x^2y^2) over (x^2y^2-xy^2)/(x^3y^4)
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(x^2-y^2)/(x^2y^2) over (xy^2(x-1)/(x^3y^4)
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Invert the denominator and multiply:
(x^2-y^2)/(x^2y^2) times (x^3y^4)/(xy^2(x-1))
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[(x^2-y^2)/(xy^2(x-1)] * [xy^2/1]
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Cheers,
Stan H.
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