SOLUTION: I'm trying to find the inverse of the following function: f(x)=ln(x-2)+1.
Here's what I have done: x=ln(y-2)+1; e^x - 1 = ln (y-2); y=(e^x-1) + 2 is what I get for an answer. Not
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-> SOLUTION: I'm trying to find the inverse of the following function: f(x)=ln(x-2)+1.
Here's what I have done: x=ln(y-2)+1; e^x - 1 = ln (y-2); y=(e^x-1) + 2 is what I get for an answer. Not
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Question 702850: I'm trying to find the inverse of the following function: f(x)=ln(x-2)+1.
Here's what I have done: x=ln(y-2)+1; e^x - 1 = ln (y-2); y=(e^x-1) + 2 is what I get for an answer. Not sure if I'm doing this correctly. Appreciate your help. Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! find the inverse of the following function: f(x)=ln(x-2)+1
y=ln(x-2)+1
interchange x and t, then solve for y
x=ln(y-2)+1
(x-1)=ln(y-2)
convert to exponential form: base(e) raised to log of the number(x-1)=number(y-2)
e^(x-1)=y-2
y=e^(x-1)+2 (same answer you got)
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