SOLUTION: I'm trying to find the inverse of y= -6^x/3. Please note, the right side of the equation reads negative 6 to the x power all divided by 3. Here's what I have so far: x=-6^y/3. I'm

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: I'm trying to find the inverse of y= -6^x/3. Please note, the right side of the equation reads negative 6 to the x power all divided by 3. Here's what I have so far: x=-6^y/3. I'm      Log On


   

Question 702849: I'm trying to find the inverse of y= -6^x/3. Please note, the right side of the equation reads negative 6 to the x power all divided by 3.
Here's what I have so far: x=-6^y/3. I'm not sure where to go from there.
Found 2 solutions by josgarithmetic, solver91311:
Answer by josgarithmetic(39630) About Me  (Show Source):
You can put this solution on YOUR website!
First step can be to switch roles of x and y, because you want the inverse.

x=-%286%5Ey%29%2F3
-3x=6%5Ey


And change the form of that into logarithmic form:
log%5B6%5D%28-3x%29=y
I'm trying to say, "y is equal to the logarithm base 6 of negative three x".

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


Start over. Your first step is incorrect. You have to solve for in terms of and only THEN do you swap the variables.

The problem is, no matter what you do, you end up with a logarithm argument that is less than zero. Since the domain of the log function is the positive reals, this dog won't hunt.

The inverse function is undefined, hence the original function is not invertible.

John

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