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Question 702805: What is the center of the circle given by the equation below?
x2 - 16x + y2 - 18y = -129
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! What is the center of the circle given by the equation below?
x2 - 16x + y2 - 18y = -129
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Complete the square on the x and on the y terms:
x^2 -16x + 64 + y^2 -18y + 81 = -129+64+81
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Factor:
(x-8)^2 + (y-9)^2 = 16
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Center: (8,9)
radius: sqrt(16) = 4
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Cheers,
Stan H.
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