Question 702563: graph of y=sec(x- pi/2)
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! graph of sec: y=(Bx-C), period=2π/B, phase shift=C/B
For given function: y=sec(x- pi/2)
B=1
C=π/2
period=2π/B=2π
1/4 period=π/2
Phase shift=C/B=π/2 (shift to the right)
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Graph for 1 period:
coordinates of basic sec function with no phase shift
(0,1), (π/2, ∞), (π, -1), (3π/2,-∞), (π/2,1)
Asymptotes:x=π/2 and x=3π/2
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π/2 phase shift to the right
(0,∞), (π/2,1), (π, ∞), (3π/2, -1), (2π,-∞), (5π/2,1)
asymptotes: x=0, x=π, x=2π
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