Question 702425: How do you find the focus, directrix, and vertex of the formula : x^2+8y=0 (Parabola)
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! How do you find the focus, directrix, and vertex of the formula :
x^2+8y=0
x^2=-8y
This is an equation of a parabola that opens downwards.
Its standard form: (x-h)^2=-4p(x-h), (h,k)=(x,y) coordinates of the vertex
For given equation:x^2=-8y
vertex: (0,0)
axis of symmetry: x=0
4p=8
p=2
focus: (0,-2) (p-distance below the vertex on the axis of symmetry)
directrix: y=2 (p-distance above the vertex on the axis of symmetry)
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