SOLUTION: What is the area of a quadrilateral with vertices at (-2,2), (-1,1), (4,1), and (3,-2).

Algebra ->  Geometry-proofs -> SOLUTION: What is the area of a quadrilateral with vertices at (-2,2), (-1,1), (4,1), and (3,-2).      Log On


   

Question 702082: What is the area of a quadrilateral with vertices at (-2,2), (-1,1), (4,1), and (3,-2).
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
The horizontal (green) segment connecting (-1,1) to (4,1) splits the quadrilateral into two triangles, and it can be considered the base of both triangles.
Its length is b=5
Their heights are h%5B1%5D=1 and h%5B2%5D=3
Their areas are
area%5B1%5D=%281%2F2%29%2A5%2A1 and area%5B2%5D=%281%2F2%29%2A5%2A3
The area of the quadrilateral is the sum:
area=%281%2F2%29%2A5%2A1%2B%281%2F2%29%2A5%2A3 --> area=%281%2F2%29%2A5%2A%281%2B3%29 --> area=%281%2F2%29%2A5%2A4 --> highlight%28area=10%29