If I had a choice, I would not solve that system by substitution. --> -->
Substituting for in we get --> --> --> --> --> .
Then, substituting for in , we get --> --> .
If I could choose how to solve it,
I would first transform the equations,
so as to get equivalent equations without fractions. --> (multiplying everything times 6) --> (multiplying everything times 12)
Then I would add both equations to get --> .
I would also subtract the second equation from the first one to get --> .
IF THE PROBLEM WAS ,
That's the same as .
That could be solve the same way for and to get and
Then the solutions would be and .