SOLUTION: Find the derivative of: If y (Y^3) - 4(x^2)y + 2(x^5) = 40
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Question 701335
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Find the derivative of:
If y
(Y^3) - 4(x^2)y + 2(x^5) = 40
Answer by
Alan3354(69443)
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Find the derivative of:
If y
(Y^3) - 4(x^2)y + 2(x^5) = 40
==========================
wrt x, I assume.
y^3 - 4x^2y + 2x^5 = 40
3y^2dy - 4x^2dy - 8xydx + 10x^4dx = 0
3y^2dy - 4x^2dy = 8xydx - 10x^4dx
(3y^2 - 4x^2)dy = (8xy - 10x^4)dx
dy/dx = (10x^4 - 8xy)/(4x^2 - 3y^2)