SOLUTION: find the equation of the circle with centre (-a,a) and radius 2a.

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Question 701329: find the equation of the circle with centre (-a,a) and radius 2a.
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
(x-h)^2+(y-k)^2=r^2

(x-(-a))^2+(y-a)^2=(2a)^2

(x+a)^2+(y-a)^2 = 4a^2

So the answer is (x+a)^2+(y-a)^2 = 4a^2