SOLUTION: 1. find the equation of the circle in standard form with center at ( -2, 1) and passing through (3, -2)

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Question 701158: 1. find the equation of the circle in standard form with center at ( -2, 1) and passing through (3, -2)
Answer by mouk(232) About Me  (Show Source):
You can put this solution on YOUR website!
The general equation of a circle with centre (a,b) and radius r is:
+%28x-a%29%5E2+%2B+%28y-b%29%5E2+=+r%5E2+

So equation of a circle in with centre at (-2, 1) is:
+%28x%2B2%29%5E2+%2B+%28y-1%29%5E2+=+r%5E2+

Circle passes through (3, -2) so:
+%283%2B2%29%5E2+%2B+%28-2-1%29%5E2+=+r%5E2+
+25+%2B+9+=+r%5E2+
+34+=+r%5E2+

Hence, the required equation is:
+%28x%2B2%29%5E2+%2B+%28y-1%29%5E2+=+34+