SOLUTION: find two consecutive natural numbers such that eight times the first is 1 less than seven times the second

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Question 700995: find two consecutive natural numbers such that eight times the first is 1 less than seven times the second
Answer by Alan3354(69443) About Me  (Show Source):
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find two consecutive natural numbers such that eight times the first is 1 less than seven times the second
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8n = 7(n + 1) - 1
8n = 7n + 7 - 1 = 7n + 6
n = 6
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--> 6 & 7