SOLUTION: find the area of Triangle ABC where a=b=c=12

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Question 700950: find the area of Triangle ABC where
a=b=c=12
Found 2 solutions by MathLover1, checkley79:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

Area+=%281%2F2%29%2Ab%2Ah where b is base and h is height
if given a=b=c=12, means you have an Equilateral Triangle and base b=12
now we need to calculate height h which could be find using Pythagorean theorem because it divides equilateral triangle into two right angle triangles; so,
h%5E2=a%5E2-%28b%2F2%29%5E2
h%5E2=12%5E2-%2812%2F2%29%5E2
h%5E2=12%5E2-6%5E2
h%5E2=144-36
h%5E2=108
h=sqrt%28108%29
h=10.39...we need only positive root because height could be only positive number

then, the area will be:
Area+=%281%2F2%29%2A12%2A10.39
Area+=6%2A10.39
Area+=62.34

Answer by checkley79(3341) About Me  (Show Source):
You can put this solution on YOUR website!
a=b=c=12
AREA=BH/2
a^2=b^2+c^2
12^2=6^2+c^2
144=36+c^2
c^2=144-36
c^2=108
c=sqrt108
c=10.39 is the height.
area=12*10.39/2
area=124.70/2
area=62.35 ans.