SOLUTION: Use the Rational Root Theorem to list all possible rational roots for each equation. Then find any actual roots.
x^3 + 2x^2 + 3x + 6 = 0
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-> SOLUTION: Use the Rational Root Theorem to list all possible rational roots for each equation. Then find any actual roots.
x^3 + 2x^2 + 3x + 6 = 0
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Question 700939: Use the Rational Root Theorem to list all possible rational roots for each equation. Then find any actual roots.
x^3 + 2x^2 + 3x + 6 = 0 Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Use the Rational Root Theorem to list all possible rational roots for each equation. Then find any actual roots.
x^3 + 2x^2 + 3x + 6 = 0
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f(-3) is negative
f(-2) is zero
f(-1) is positive
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Using synthetic division:
-2)....1....2....3....6
........1....0....3...|..0
x = -2 is a rational zero.
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Find other roots:
Quotient: x^2 + 3
Solve: x^2+3 = 0
x^2 = -3
x = sqrt(3)i or x = -sqrt(3)i
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Cheers,
Stan H.
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