We'll need the slope formula first
m =
And then we will need point-slope formula:
y - y1 = m(x - x1)
(-2,a) and (a,3) has slope -1/2
m =
m =
m =
We are give that that equals
=
=
Cross multiply:
2(3-a) = -1(a+2)
6-2a = -a-2
-a = -8
a = 8
So the points
(-2,a) and (a,3) become the points
(-2,8) and (8,3)
Using the point-slope form:
y - y1 = m(x - x1)
(-2,8)
y - 8 =
(x - (-2) )
y - 8 =
(x + 2)
Multiply both sides by 2
2(y - 8) = 2×
(x + 2)
2y - 16 = -1(x + 2)
2y - 16 = -x - 2
x + 2y = 14
Edwin