SOLUTION: You have a choice of two different Internet service company's company a charges $12 per month plus $2.00 per hour. Company b charges $27 per month plus .50 per hour. How many hours

Algebra ->  Human-and-algebraic-language -> SOLUTION: You have a choice of two different Internet service company's company a charges $12 per month plus $2.00 per hour. Company b charges $27 per month plus .50 per hour. How many hours      Log On


   



Question 700579: You have a choice of two different Internet service company's company a charges $12 per month plus $2.00 per hour. Company b charges $27 per month plus .50 per hour. How many hours would you need to use the Internet per month for the services to be the same price?
Answer by checkley79(3341) About Me  (Show Source):
You can put this solution on YOUR website!
12+2X=27+.5X
2X-.5X=27-12
1.5X=15
X=15/1.5
X=10 HOURS.
PROOF:
12+2*10=27+.5*10
12+20=27+5
32=32