SOLUTION: The measures of two supplementary angles are 6y + 3 and 4y - 13.Find the measures of the angles.

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Question 700301: The measures of two supplementary angles are 6y + 3 and 4y - 13.Find the measures of the angles.
Found 2 solutions by rfer, MathLover1:
Answer by rfer(16322) About Me  (Show Source):
You can put this solution on YOUR website!
6y+3+4y-13=180
10y=180+10
10y=190
y=190/10
y=19
6y+3=117
4y-13=63

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

two supplementary angles alpha and beta add up to 180°
so, alpha%2Bbeta=180°
if alpha=6y+%2B+3 and beta=4y+-13, than we have

6y+%2B+3%2B4y+-13=180°...solve for y

10y+-10=180°
10y+=180%2B10°
10y+=190°
y+=190%2F10°
y+=19°......now find alpha and beta

alpha=6y+%2B+3° ...plug in y value
alpha=6%2A19+%2B+3°
alpha=114+%2B+3°
highlight%28alpha=117%29°


and beta=4%2A19+-13°
beta=76+-13°
highlight%28beta=63%29°