SOLUTION: The owner of a movie theater was counting the money from one day's ticket sales. He knew that a total of 150 tickets were sold. Adult tickets cost $7.50 each and children's tickets

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Question 700285: The owner of a movie theater was counting the money from one day's ticket sales. He knew that a total of 150 tickets were sold. Adult tickets cost $7.50 each and children's tickets cost $4.75 each. If the total receipts for the day were $891.25, how many of each kind of ticket were sold?
Found 2 solutions by mananth, solver91311:
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
x= number of child tickets
y= number of adult tickets
Total sold
1.00 x + 1.00 y = 150.00 .............1
Total value
4.75 x + 7.50 y = 891.25 .............2
Eliminate y
multiply (1)by -7.50
Multiply (2) by 1.00
-7.50 x -7.50 y = -1125.00
4.75 x + 7.50 y = 891.25
Add the two equations
-2.75 x = -233.75
/ -2.75
x = 85.00
plug value of x in (1)
1.00 x + 1.00 y = 150.00
85.00 + y = 150.00
y = 150.00 -85.00
y = 65.00
y = 65.00
x= 85 number of child tickets
y= 65 number of adult tickets
m.ananth@hotmail.ca

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


Let represent the number of Adults and represent the number of Children. Then



and



Solve the system for and

John

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