SOLUTION: My Algebra homework has the number problem : The sum of two numbers is 15. Three times one of the numbers is 11 less than five times the other. Find the numbers.

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Question 700135: My Algebra homework has the number problem : The sum of two numbers is 15. Three times one of the numbers is 11 less than five times the other. Find the numbers.
Found 2 solutions by josmiceli, stanbon:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let the numbers be +x+ and +y+
given:
(1) +x+%2B+y+=+15+
(2) +3x+=+5y+-+11+
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(2) +3x+-+5y+=+-11+
Multiply both sides of (1) by +3+
and subtract (2) from (1)
(1) +3x+%2B+3y+=+45+
(2) +-3x+%2B+5y+=+11+
+8y+=+56+
+y+=+7+
and, since
(1) +x+%2B+y+=+15+
(1) +x+%2B+7+=+15+
(1) +x+=+8+
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The numbers are 7 and 8
check:
(2) +3x+=+5y+-+11+
(2) +3%2A8+=+5%2A7+-+11+
(2) +24+=+35+-+11+
(2) +24+=+24+
OK


Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
The sum of two numbers is 15. Three times one of the numbers is 11 less than five times the other.
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Equations:
x + y = 15
3x = 5y-11
------
Rearrange:
3x + 3y = 3*15
3x - 5y = -11
----
Subtract and solve for "y":
8y = 56
y = 7
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Cheers,
Stan H.
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