SOLUTION: 13/12 x + 1/12 x = 9x+ 1/6 + 11/12 How do I work this problem to obtain the right answer ?13 is at the top and 12 is on bottom as 1 over 2 and 1 over 6 and 11 ove
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-> SOLUTION: 13/12 x + 1/12 x = 9x+ 1/6 + 11/12 How do I work this problem to obtain the right answer ?13 is at the top and 12 is on bottom as 1 over 2 and 1 over 6 and 11 ove
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Question 69948: 13/12 x + 1/12 x = 9x+ 1/6 + 11/12 How do I work this problem to obtain the right answer ?13 is at the top and 12 is on bottom as 1 over 2 and 1 over 6 and 11 over 12. Thanks for your help and how to work the problem. Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! 13/12 x + 1/12 x = 9x+ 1/6 + 11/12 How do I work this problem to obtain the right answer ?13 is at the top and 12 is on bottom as 1 over 2 and 1 over 6 and 11 over 12. Thanks for your help and how to work the problem.
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The problem as I see it, assume you meant the 2nd term as 1/2 instead of 1/12:
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It would be easier to solve if we got rid of all these denominators, do you agree?
Note that the common denominator would be 12 and as long as we multiply every
term by 12 we will preserve equality, right?
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We can do some serious canceling here, resulting in:
13x + 6x = 12(9x) + 2(1) + 11
13x + 6x = 108x + 2 + 11
19x = 108x + 13
19x - 108x = 13
-89x = 13
x = 13/-89
x = -.146 a pretty nasty number
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Let's substitute it for x in the original eq and see if it works:
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Using a calculator and decimals of course
-.158 - .073 = -1.314 + .167 + .916
.231 = .231; equality reigns
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Hope this clarifies things for you.
