SOLUTION: The sum of the digits of a two-digit number is 13. When the digits are reversed, the new number is 27 more than the original number. What is the original number?
Algebra ->
Customizable Word Problem Solvers
-> Numbers
-> SOLUTION: The sum of the digits of a two-digit number is 13. When the digits are reversed, the new number is 27 more than the original number. What is the original number?
Log On
Question 699408: The sum of the digits of a two-digit number is 13. When the digits are reversed, the new number is 27 more than the original number. What is the original number? Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! let the digitd be x & y. x in the ten's place
x+y =13.....................(1)
reversed
10y+x= 27+10x+y
9y-9x=27
/9
y-x=3...................(2)
add (1) & (2)
we get 2y=16
/2
y=8
if y =8 then x= 5
so the number is (xy) 58
