SOLUTION: How do I solve the following problem for X? Please exact or round to hundredths. 7^2x+1=3^x+2

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Question 698920: How do I solve the following problem for X? Please exact or round to hundredths.
7^2x+1=3^x+2
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Assume the problem is:
7%5E%28%282x%2B1%29%29+=+3%5E%28%28x%2B2%29%29
using logs
log%287%5E%28%282x%2B1%29%29%29+=+log%283%5E%28%28x%2B2%29%29%29
The log equiv of exponents
(2x+1)log(7) = (x+2)log(3)
Find the logs of 7 and 3
.8451(2x+1) = .4771(x+2)
1.6902x + .8451 = .4771x + .9542
1.6901x - .4771x = .9542 - .8451
1.213x = .1091
x = .1091%2F1.213
x ~ .09
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You can check this on your calc, replace x with .09 in the 1st equation, confirm they are equal