SOLUTION: Find the perimeter of a rhombus if the diagnals have lengths 20 and 48.

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Question 698645: Find the perimeter of a rhombus if the diagnals have lengths 20 and 48.
Found 2 solutions by sofiyac, MathLover1:
Answer by sofiyac(983) About Me  (Show Source):
You can put this solution on YOUR website!
BC^2 = 10^2 + 24^2
BC = 26 meters.

We now evaluate the perimeter P as follows:
P = 4 * 26 = 104 meters.
You can look up the picture to this problem here...search for Problem 2
http://www.analyzemath.com/Geometry/rhombus_problems.html

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

The rhombus is a parallelogram with four congruent sides.
if the diagnals have lengths d%5B1%5D=20 and d%5B2%5D=48, then the point O is intersection point and midpoint for both diagonals; it means, if you consider right angle triangle BOC side OC=20%2F2=10 and side OB=48%2F2=24
using Pythagorean theorem we can find side of rhombus BC
BC%5E2=OC%5E2%2BOB%5E2
BC%5E2=10%5E2%2B24%5E2
BC%5E2=100%2B576
BC%5E2=676
BC=sqrt%28676%29
BC=26
perimeter:
P=4%2A26
P=104