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Question 698435: I have so much trouble with matrices, I wish I could be better at them. I'm trying to solve the system.
I have the system:
{3x + 2y = -6
{2x - 3y = 61
I converted the system into a matrix equation:
|3, 2|
|2,-3|
Find the determinate:
(3*-3)-(2*2)
-13
So since I got -13, it would appear as 1/-13. right?
After getting that, I changed matrix equation into:
|-3,-2|
|-2, 3|
And I'm stuck here. It's probably hard to comprehend what I'm trying to say, but please help me with the rest of the problem.
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! I have so much trouble with matrices, I wish I could be better at them. I'm trying to solve the system.
I have the system:
{3x + 2y = -6
{2x - 3y = 61
I converted the system into a matrix equation:
|3, 2|
|2,-3|
Find the determinate: (determinant)
(3*-3)-(2*2)
-13
So since I got -13, it would appear as 1/-13. right? *** Doesn't matter.
After getting that, I changed matrix equation into:
|-3,-2|
|-2, 3| **** that's not useful.
=================================
Use the augmented matrix.
|3, 2 6|
|2,-3 -61|
------------
Block the x column
|+2 6|
|-3 -61|
--> 2*-61 + 18 = -104
x = -104/Det = 8
===================
|3, 2 6|
|2,-3 -61|
Block the y column
|3 6|
|2,- 61|
--> 3*-61 - 12 = 195
-y = -195/-13 (not the minus sign)
y = -15
===================
And I'm stuck here. It's probably hard to comprehend what I'm trying to say, but please help me with the rest of the problem.
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