SOLUTION: write the equaton of the parabola y=x^2-8x-87 in standard form. a. y+16=(x-4)^2 c. y+103=(x-4)^2 b. y+87=(x-4)^2 d. y-4=(x-4)^2

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: write the equaton of the parabola y=x^2-8x-87 in standard form. a. y+16=(x-4)^2 c. y+103=(x-4)^2 b. y+87=(x-4)^2 d. y-4=(x-4)^2      Log On


   

Question 698410: write the equaton of the parabola y=x^2-8x-87 in standard form.
a. y+16=(x-4)^2 c. y+103=(x-4)^2
b. y+87=(x-4)^2 d. y-4=(x-4)^2
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

The standard form of a parabola's equation is generally expressed:
y+=+ax%5E2+%2B+bx+%2B+c

The vertex form of a parabola's equation is generally expressed as :
y=+a%28x-h%29%5E2%2Bk+

y=x%5E2-8x-87....write -87 as 16-103 to complete square
y=x%5E2-8x%2B16-103
y=%28x%5E2-8x%2B4%5E2%29-103
y=%28x-4%29%5E2-103
answer is:
c. y%2B103=%28x-4%29%5E2 or y=%28x-4%29%5E2+-103