Question 69831: Twice the sum of a number and -6 equals -6 times the sum of the number and 4. Let n stand for the number. Solve for n. Answer by ptaylor(2198) (Show Source):
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Let n=the number
2(n-6)=twice the sum of the number and -6:
-6(n+4)=-6 times the sum of the number and 4
And we are told that the above two quantities are equal. So our equation to solve is:
2(n-6)=-6(n+4) get rid of parens
2n-12=-6n-24 add 6n and also 12 to both sides
2n+6n-12+12=-6n+6n-24+12 collect like terms
8n=-12 divide both sides by n
n=-12/8=-3/2=-1.5--------------------------------the number
ck
2(-1.5-6)=-6(-1.5+4)
2(-7.5)=-6(2.5)
-15=-15