Question 698265: How do i graph y=2x^2+4 what are the steps in solving to get the vertex and the axis of symmetry and then find the parabula? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! How do i graph y=2x^2+4 what are the steps in solving to get the vertex and the axis of symmetry and then find the parabula?
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Vertex occurs where x = -b/(2a) = -0/(2*2) = 0
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The y-coordinate of the vertex is f(0) = 4
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Vertex: (0,4)
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The axis of symmetry is a vertical line thru the axis:
Its equatiion is x = 0
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Cheers,
Stan H.
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