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given: mi
Let = usual rate
Let = time to go 180 mi at usual rate = faster rate = time to go 180 mi at faster rate
--------------
At usual rate:
(1)
At faster rate:
(2)
----------------------------
(2)
and
(1)
Substitute this into (2)
(2)
(2)
Multiply both sides by
(2)
(2)
Use quadratic formula
Your usual speed is 45 mi/hr
Your faster speed is 60 mi/hr
check answer:
(1)
(1)
(1) hrs
and
(2)
(2)
(20
OK