SOLUTION: find the smallest number which when divided by 24 and 36 leaves remainder 8 in each case?

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Question 698095: find the smallest number which when divided by 24 and 36 leaves remainder 8 in each case?
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
24=2%2A12 and 36=3%2A12 so LCM%2824%2C32%29=2%2A3%2A12=6%2A12=72
n = number that divided by 24 and 36 leaves remainder 8 in each case
n-8 divides evenly by 24 and 36
So n-8 is a multiple of 72 (the LCM of 24 and 36)
The smallest such n-8 is 72
The smallest n is 72%2B8=highlight%2880%29