SOLUTION: leaving from her home, mindy jogged at the rate 4 mph and walked back at the rate 2 mph. if she spent a total of 6 hours on her trip without stopping, how far did her trip take her
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Question 697652: leaving from her home, mindy jogged at the rate 4 mph and walked back at the rate 2 mph. if she spent a total of 6 hours on her trip without stopping, how far did her trip take her from home ? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! leaving from her home, mindy jogged at the rate 4 mph and walked back at the rate 2 mph.
if she spent a total of 6 hours on her trip without stopping, how far did her trip take her from home ?
:
let d = the one-way distance
:
Write a time equation; Time = dist/speed
:
Jog time + walk time = 6 hrs + = 6
multiply by 4, to clear the denominators, results:
d + 2d = 4(6)
3d = 24
d = 24/3
d = 8 miles from home
:
:
Confirm this by finding the time of each way.
8/4 = 2hrs
8/2 = 4hrs
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total: 6 hrs
