SOLUTION: 1. Ellen wishes to mix candy worth $2.17 per pound with candy worth $3.55 per pound to form 24 pounds of a mixture worth $3.09 per pound. How many pounds of the more expensive cand
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-> SOLUTION: 1. Ellen wishes to mix candy worth $2.17 per pound with candy worth $3.55 per pound to form 24 pounds of a mixture worth $3.09 per pound. How many pounds of the more expensive cand
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Question 69765This question is from textbook Intermediate algebra
: 1. Ellen wishes to mix candy worth $2.17 per pound with candy worth $3.55 per pound to form 24 pounds of a mixture worth $3.09 per pound. How many pounds of the more expensive candy should she use?
2. A cruise boat travels 84 miles downsteam in 3 hours and returns to its starting point upstream in 6 hours. Find the speed of the stream.
I can't figure out the equations for either one of these word problems!! This question is from textbook Intermediate algebra
You can put this solution on YOUR website! 1. Ellen wishes to mix candy worth $2.17 per pound with candy worth $3.55 per pound to form 24 pounds of a mixture worth $3.09 per pound. How many pounds of the more expensive candy should she use?
Let amt. of 2.17 candy be "x" lbs. ;Value of this is 217x cents
Amt of 3.55 candy is "24-x" lbs. Value is 355(24-x)= 8520-355x cents
Amt of mixture is 24 lbs; Value is 309(24)=7416 cents
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EQUATION:
value + value = 7416 cents
217x + 8520-355x = 7416
-138x=-1104
x=8 lbs (amt of $2.17 candy in the mixture)
24-x= 16 lbs (amt of $3.55 candy in the mixture)
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2. A cruise boat travels 84 miles downsteam in 3 hours and returns to its starting point upstream in 6 hours. Find the speed of the stream.
Downstream DATA:
distance = 84 miles; time = 3 hrs; rate= d/t=84/3 = 28 mph
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Upstream DATA:
distance = 84 miles ; time 6 hrs; rate = d/t = 84/6 = 14 mph
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boat speed + stream = 28 mph
boat speed - stream = 14 mph
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Add the two equations to get:
2b=42
b=21
Then 21 + stream speed = 28 mph
stream speed = 7 mph
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Cheers,
Stan H.
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