SOLUTION: Elmore and Sonjay cross-country skied along the same trail. Sonjay skied at 12ft/s. Elmore skied at 15ft/s and started down the trail 2 min after Sonjay started. The two skiers re
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Question 697495: Elmore and Sonjay cross-country skied along the same trail. Sonjay skied at 12ft/s. Elmore skied at 15ft/s and started down the trail 2 min after Sonjay started. The two skiers reached the first fork in the trail at the same time.
a. How long after Sonjay started did the two skiers meet?
b. How far was it to the first fork? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Elmore and Sonjay cross-country skied along the same trail.
Sonjay skied at 12ft/s.
Elmore skied at 15ft/s and started down the trail 2 min after Sonjay started.
The two skiers reached the first fork in the trail at the same time.
:
a. How long after Sonjay started did the two skiers meet?
Change 2 min to 120 sec
let t = S's skiing time
then
(t-120) = E's skiing time
:
When E catches S, they will have traveled the same dist
write distance equation; dist = speed * time
:
E's dist = S's dist
15(t-120) = 12t
15t - 1800 = 1t
15t - 12t = 1800
3t = 1800
t = 600 secs (10 min) after S starts, is caught by E
:
:
b. How far was it to the first fork?
12(600) = 7200 ft
check
15(600-120) = 7200 ft
