SOLUTION: Solve for x 5+ log x = log x^6 any help you can give would be greatly appreciated

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Question 697335: Solve for x
5+ log x = log x^6
any help you can give would be greatly appreciated
Answer by Positive_EV(69) About Me  (Show Source):
You can put this solution on YOUR website!
log%28x%5Ea%29+=+a%2Alog%28x%29, so log%28x%5E6%29+=+6%2Alog%28x%29.
5+%2B+log%28x%29+=+6%2Alog%28x%29, subtract log(x) from both sides:
5+=+5%2Alog%28x%29, divide both sides by 5:
1+=+log%28x%29. Since log with no base given usually denotes log base 10, you want the value of x for which:
10%5E1+=+x, so x = 10.